Practice question
Question
A 3 M solution of NaCl has a density of 1.25 g/mL. What is its molality? (Molar mass of NaCl = 58.5 g/mol)
Explanation
Mass of 1 L solution = 1000 × 1.25 = 1250 g. Mass of NaCl = 3 × 58.5 = 175.5 g. Mass of water = 1250 − 175.5 = 1074.5 g = 1.0745 kg. Molality = 3 / 1.0745 ≈ 2.79 m.
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