Practice question
Question
A 2 kg block slides down a frictionless incline from 9 m height. What is its speed at the bottom? (Take g = 10 m/s² )
Explanation
Given:
A 2 kg block slides down a frictionless incline from 9 m height. What is its speed at the bottom? (Take g = 10 m/s² )
Formula:
Potential energy mgh = 2 × 10 × 9 = 180 J.
Substitution & Calculation:
Kinetic energy 1/2 m v² = 180 Rightarrow v² = 180 Rightarrow v = √180 approx 13.42 m/s .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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