Practice question
Question
A 1kg pendulum bob completes a vertical circle of radius 2.2m. What is the speed at the bottom? (Take g\=10m/s2)
Explanation
At top, vC=gL, energy conservation: 12mv02=12m(gL)+2mgL. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 m/s. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.