Practice question
Question
A \( 10 \, \text{V} \) battery with negligible internal resistance is connected to a \( 2 \, \Omega \)
and \( 3 \, \Omega \) resistor in series. What is the power dissipated in the \( 3 \, \Omega \)
resistor?
Explanation
**Cells combination** series ε_eq = Σ ε_i, r_eq = Σ r_i, parallel for identical cells ε_eq = ε, r_eq = r/n, n number of cells. Maximum current when external R = r_eq, power transfer theorem, explaining why matching resistances maximizes power. Total resistance: R = 2 + 3 = 5 Ω . Current: I = (V/R) = (10/5) = 2 A . Power: P = I² R = 2² × 3 = 12 W . Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.