Practice question
Question
Why does the electric field inside a dielectric material decrease when placed in an external field,
compared to the field in free space?
Explanation
**Conductor in electrostatic equilibrium** has E=0 inside, charges reside on surface, potential constant throughout conductor. Hollow shell with no internal charge has zero field inside cavity, even if external field present, charges on outer surface screen interior, principle used in Faraday cage. When a dielectric is placed in an external field E₀ , it polarizes, creating bound charges that produce an internal field Eiₙducₑd opposing E₀ . The net field inside the dielectric is E = (E₀/K) , where K > 1 is the dielectric constant. For linear dielectrics, K > 1 , so E < E₀ , as the polarization reduces the effective field
Discussion
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