Practice question
Question
What happens to the period of a spring-mass system if both the mass and spring constant are doubled?
Explanation
**Effect of damping** is gradual amplitude reduction while period remains nearly constant for light damping. Mechanical energy decreases as work done against damping force, E(t) = ½ k A(t)² decaying exponentially, and motion ceases without external energy input, distinguishing from ideal undamped SHM. Period T = 2π √((m/k)) . If m' = 2m and k' = 2k , then T' = 2π √((2m/2k)) = 2π √((m/k)) = T , so the period remains unchanged. Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result It remains unchanged follows, reflecting SHM dependence on
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