Practice question
Question
For FeO(s) + CO(g) <=> Fe(s) + COâ‚‚(g), K_p = 0.5 atm at 1000 K. If initial p_{CO = 1 atm, what is p_{COâ‚‚ at equilibrium?
Explanation
Given:
For FeO(s) + CO(g) <=> Fe(s) + COâ‚‚(g), K_p = 0.5 atm at 1000 K. If initial p_{CO = 1 atm, what is p_{COâ‚‚ at equilibrium?
These values define the system as per NCERT data.
Formula:
Let p_{COâ‚‚ = x, p_{CO = 1 - x.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Solids are omitted. K_p = fracp_{COâ‚‚p_{CO = x/1 - x = 0.5 . x = 0.5 - 0.5x, 1.5x = 0.5, x = 0.333 atm.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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