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Practice question

Question

For FeO(s) + CO(g) <=> Fe(s) + COâ‚‚(g), K_p = 0.5 atm at 1000 K. If initial p_{CO = 1 atm, what is p_{COâ‚‚ at equilibrium?

Options

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Explanation

Given: For FeO(s) + CO(g) <=> Fe(s) + CO₂(g), K_p = 0.5 atm at 1000 K. If initial p_{CO = 1 atm, what is p_{CO₂ at equilibrium? These values define the system as per NCERT data. Formula: Let p_{CO₂ = x, p_{CO = 1 - x. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Solids are omitted. K_p = fracp_{CO₂p_{CO = x/1 - x = 0.5 . x = 0.5 - 0.5x, 1.5x = 0.5, x = 0.333 atm. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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