Practice question

Given: Calculate the power of a laser emitting 5.0 × __10POW₂₄__photons per second at 589 nm. (h = 6.626 × 10⁻³⁴J s, c = 3.0 × __10POW₈__m s^{-1) These values define the system as per NCERT data. Formula: Energy per photon E = hc/lambda = frac6.626 × 10⁻³⁴ × 3.0 × __10POW₈₅₈₉__ × 10⁻⁹= 3.375 × 10⁻¹⁹J. This is standard NCERT relation. Substitution & Calculation: Power = 5.0 × __10POW₂₄__ × 3.375 × 10⁻¹⁹= 1.6875 × __10POW₆__W. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.