Practice question

**Pendulum motion** exhibits isochronism for small amplitudes, period depends only on L and g. Using g = 9.8 m/s², T calculation requires √(L/g), frequency reciprocal of period. Angular frequency directly √(g/L), e.g., L = 0.25 m gives T ≈ 1.0 s. Period: T = 2π √((L/g)) . T = 2 × 3.14 √((0.25/9.8)) = 6.28 √(0.0255) ≈ 6.28 × 0.16 ≈ 1.0 s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 1.0 s follows, reflecting SHM dependence on amplitude A, ω and system parameters.