Practice question

Given: A neutron ( 1 u ) at 10⁶m/s collides elastically with a carbon ( 12 u ). What fraction of its kinetic energy is transferred? Formula: Fraction transferred f_2 = 4 m_1 m_2/(m_1 + m_2)² = 4 × 1 × 12/(1 + 12)² = 48/169 approx 0.284 .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.