Practice question

**Capacitive reactance** X_C =1/(ω C)=1/(2π f C) (Ω), C capacitance (F), current leads voltage by 90°, I_rms = V_rms/X_C = V_rms ω C, I_peak = V_peak ω C, impedance Z = X_C for pure C. For 45 μF, 60 Hz, X_C=1/(2π×60×45×10⁻⁶)=58.9 Ω, V_rms=110 V, I_rms=1.867 A, I_peak=2.64 A. X_L = ω L , ω = 2π × 60 = 376.8 rad/s . L = 75 × 10⁻³ H . X_L = 376.8 × 0.075 = 28.26 Ω . RMS current: I = (V/X_L) = (110/28.26) ≈ 3.89 A . Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms =