Practice question

**Capacitor average power** zero over complete cycle because P=V I =½ V_peak I_peak sin2ωt average zero, energy stored in field, not dissipated, unlike resistor. For 15 μF, 60 Hz, X_C=176.8 Ω, V_rms=110 V, I_rms=0.622 A, illustrating lower C higher X_C. X_C = (1/ω C) , ω = 2π × 60 = 376.8 rad/s . C = 20 × 10⁻⁶ F . X_C = (1/376.8 × 20 × 10⁻⁶) ≈ 132.7 Ω . RMS current: I = (V/X_C) = (110/132.7) ≈ 0.829 A . Peak current: i_m = √(2) I = 1.414 × 0.829 ≈ 1.17 A . Applying X_L = ωL, X_C = 1/ωC, Z