Calculate the work done when 2 mol of an ideal gas expands adiabatically and reversibly from 10 L to 20 L at 600 K (γ =
T₂ = 600 × (10/20)⁰.⁴ = 600 × 0.7579 = 454.74 K, Cv = R/(γ-1) = 8.314 / 0.4 = 20.785 J/mol·K, w = nCvΔ T = 2 × 20.785 × (454.74 - 600) = -6042 J.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Thermodynamic Terms - System Surroundings and Types of Systems