Practice question
Question
Calculate the work done when 2 mol of an ideal gas expands adiabatically and reversibly from 10 L to 20 L at 600 K (γ = 1.4). (R = 8.314 J/mol·K)
Explanation
T₂ = 600 × (10/20)⁰.⁴ = 600 × 0.7579 = 454.74 K, Cv = R/(γ-1) = 8.314 / 0.4 = 20.785 J/mol·K, w = nCvΔ T = 2 × 20.785 × (454.74 - 600) = -6042 J.
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