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#four masses

2 public questions tagged with this topic.

Temperature Scales and Triple Point

Four equal masses of 3kg are at the vertices of a square with side 2m. What is the net force on one mass? (G\=6.67×10−11

Force from adjacent: F1 = Gm2r2 = 6.67×10−113×322 = 1.50×10−10N (2 forces at 90°). Force from diagonal: F2 = Gm2(22)2 = 6.67×10−1198 = 7.50×10−11N. Resultant of two F1: FR = 2×1.50×10−10≈2.12×10−10N. Net force (vector sum with F2): F = (2.12×10−10)2+(7.50×10−11)2≈2.25×10−10N.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Orbital Velocity and Time Period

Four 8kg masses form a square of side 8m. What is the potential energy of the system? (G\=6.67×10−11N m2/kg2)

4 sides: r = 8m, 2 diagonals: r = 82m. V = −4Gm28−2Gm282. V = −6.67×10−11×64(48+282). V = −4.269×10−9(0.5+0.177)≈−2.89×10−9J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -2.9 × 10⁻⁹ J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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