Skip to content
Login Register

Practice question

MCQ

Question

Four equal masses of 3kg are at the vertices of a square with side 2m. What is the net force on one mass? (G\=6.67×10−11N m2/kg2)

Options

Choose one · Correct answer highlighted

Explanation

Force from adjacent: F1 = Gm2r2 = 6.67×10−113×322 = 1.50×10−10N (2 forces at 90°). Force from diagonal: F2 = Gm2(22)2 = 6.67×10−1198 = 7.50×10−11N. Resultant of two F1: FR = 2×1.50×10−10≈2.12×10−10N. Net force (vector sum with F2): F = (2.12×10−10)2+(7.50×10−11)2≈2.25×10−10N.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.

Related blogs

Guides and insights connected to this topic