Minimum speed to escape from 10RE from Earth’s center

Practice question

Question

What is the minimum speed to escape from 10RE from Earth’s center? (g\=9.8m/s2,RE\=6.4×106m)

Options

Choose one · Correct answer highlighted

3.4 km/s 3.5 km/s Correct 3.6 km/s 3.7 km/s

Explanation

ve = 2gRE210RE = 2×9.8×6.4×10610. ve = 1.254×107≈3.54×103m/s≈3.5km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.5 km/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

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