Skip to content

Question

Water (ρ\=1000kg/m3) flows horizontally at 5.0m/s with pressure 2.1×105Pa. If the speed increases to 7.5m/s, what is the new pressure?

Options

Choose one · Correct answer highlighted

Explanation

Bernoulli’s equation: P1+12ρv12 = P2+12ρv22. P1 = 2.1×105Pa, v1 = 5.0m/s, v2 = 7.5m/s, ρ = 1000kg/m3. P2 = 2.1×105+12×1000(25−56.25) = 2.1×105−15625 = 1.94375×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.94 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.