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#vector addition

11 public questions tagged with this topic.

What fundamental principle allows the electric field due to multiple charges to be calculated as the vector sum of the f

**Vector addition of forces** underlies multi-charge analysis. Each pair contributes independent Coulomb force, resultant obtained by resolving components along axes. Equilibrium occurs when vector sum vanishes, often at symmetric points where contributions balance. The superposition principle states that the electric field produced by multiple charges is the vector sum of the fields produced by each charge independently. This principle holds because electric forces and fields are linear and unaffected by the presence of other charges. Substituting values gives Superposition, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.

Ref: NCERT > Physics Book > Electric Charges and Fields > Superposition Principle and Equilibrium of Charges

Three masses of 18kg each form an equilateral triangle with side 12m. What is the net force on one mass? (G\=6.67×10−11N

Force between two masses: F = Gm2r2 = 6.67×10−1118×18122 = 1.50×10−10N. Two forces at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (1.50×10−10)2(1+1+1) = 1.50×10−103. FR≈2.60×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.6 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

Three masses of 6kg each form an equilateral triangle with side 5m. What is the net force on one mass? (G\=6.67×10−11N m

Force between two masses: F = Gm2r2 = 6.67×10−116×652 = 9.61×10−11N. Two forces at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (9.61×10−11)2(1+1+1) = 9.61×10−113. FR≈1.66×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.7 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

Three masses of 10kg each form an equilateral triangle with side 7m. What is the net force on one mass? (G\=6.67×10−11N

Force between two masses: F = Gm2r2 = 6.67×10−1110×1072 = 1.36×10−10N. Two forces at 60°: FR = F2+F2+2F2cos⁡60∘. FR = (1.36×10−10)2(1+1+1) = 1.36×10−103. FR≈2.36×10−10N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.4 × 10⁻¹⁰ N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A boat sails east at 8m/s while a current flows north at 6m/s. What is the magnitude of the boat’s velocity relative to

Velocity components: vx=8m/s,vy=6m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 10 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations

A particle has an initial velocity of 3 î m/s and a constant acceleration of 2 ĵ m/s². What is the magnitude of its disp

Displacement r = v₀ t + (1/2) a t². As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 9 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations

A boat travels west at 6m/s while a current flows south at 8m/s. What is the magnitude of the boat’s velocity relative t

Velocity components: vx=−6m/s,vy=−8m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 10 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

A cyclist moves east at 18m/s while the wind blows south at 24m/s. What is the magnitude of the relative velocity of the

Relative velocity vwc=vw−vc, where vc=18i^,vw=−24j^. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 30 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

A swimmer moves north at 3m/s in a river flowing west at 4m/s. What is the magnitude of the swimmer’s velocity relative

Velocity components: vx=−4m/s,vy=3m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8

A boat moves north at 20 km/h while a river current flows east at 15 km/h. What is the magnitude of the resultant veloci

Resultant velocity R = √(v\_x² + v\_y²). As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 25 km/h as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Straight Line Motion - Mixed Concepts

A plane flies east at 40m/s while a wind blows north at 30m/s. What is the magnitude of the plane’s velocity relative to

Velocity components: vx=40m/s,vy=30m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 50 m/s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Equations of Motion and Problem Solving