#Torricelli's law

Viscosity, Stokes' Law and Reynolds Number

Why does a liquid jet emerging from a small hole maintain a constant range until near the hole?

Torricelli’s law (v = 2gh) shows that the efflux speed depends only on depth, remaining constant near the hole until external factors (e.g., air resistance or gravity’s vertical effect) alter its trajectory.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Viscosity, Stokes' Law and Reynolds Number

A tank has a hole 0.9m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=10m/s2)

Torricelli’s law: v = 2gh. g = 10m/s2, h = 0.9m. v = 2×10×0.9 = 18≈4.24m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.2 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Bernoulli's Theorem and Applications

A tank has a hole 1.5m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=10m/s2)

Torricelli’s law: v = 2gh. g = 10m/s2, h = 1.5m. v = 2×10×1.5 = 30≈5.48m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.5 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Equation of Continuity and Flow Rate

A tank has a hole 1.7m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 1.7m. v = 2×9.8×1.7 = 33.32≈5.77m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Viscosity, Stokes' Law and Reynolds Number

A tank has a hole 0.7m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 0.7m. v = 2×9.8×0.7 = 13.72≈3.7m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.7 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Viscosity, Stokes' Law and Reynolds Number

A tank has a hole 1.1m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=10m/s2)

Torricelli’s law: v = 2gh. g = 10m/s2, h = 1.1m. v = 2×10×1.1 = 22≈4.69m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.7 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Bernoulli's Theorem and Applications

A tank has a hole 1.4m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 1.4m. v = 2×9.8×1.4 = 27.44≈5.24m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.2 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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