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#Torricelli's law

10 public questions tagged with this topic.

PHYSICS

A hole is made 1.2 m below the surface of a tank open to the atmosphere. What is the efflux speed? (Take g = 9.8 m/s² )

Given: A hole is made 1.2 m below the surface of a tank open to the atmosphere. What is the efflux speed? (Take g = 9.8 m/s² ) These values define the system as per NCERT data. Formula: Torricelli’s law: v = sqrt2 g h. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: g = 9.8 m/s², h = 1.2 m . v = sqrt2 × 9.8 × 1.2 = sqrt23.52 approx 4.85 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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Viscosity, Stokes' Law and Reynolds Number

A tank has a hole 0.9m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=10m/s2)

Torricelli’s law: v = 2gh. g = 10m/s2, h = 0.9m. v = 2×10×0.9 = 18≈4.24m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.2 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Bernoulli's Theorem and Applications

A tank has a hole 1.5m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=10m/s2)

Torricelli’s law: v = 2gh. g = 10m/s2, h = 1.5m. v = 2×10×1.5 = 30≈5.48m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.5 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Equation of Continuity and Flow Rate

A tank has a hole 1.7m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 1.7m. v = 2×9.8×1.7 = 33.32≈5.77m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Viscosity, Stokes' Law and Reynolds Number

A tank has a hole 0.7m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 0.7m. v = 2×9.8×0.7 = 13.72≈3.7m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.7 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Viscosity, Stokes' Law and Reynolds Number

A tank has a hole 1.1m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=10m/s2)

Torricelli’s law: v = 2gh. g = 10m/s2, h = 1.1m. v = 2×10×1.1 = 22≈4.69m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.7 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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Bernoulli's Theorem and Applications

A tank has a hole 1.4m below the water surface, open to the atmosphere. What is the efflux speed? (Take g\=9.8m/s2)

Torricelli’s law: v = 2gh. g = 9.8m/s2, h = 1.4m. v = 2×9.8×1.4 = 27.44≈5.24m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.2 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

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