A particle in SHM has \( x = 7 \sin (3t + \frac{\pi}{6}) \) (in m). What is its acceleration at \( t = 0 \, \text{s} \)?
**General equation of SHM** x = A sin(ωt + φ) or A cos(ωt + φ) includes amplitude A (m), angular frequency ω = √(k/m) (rad/s) for spring system, and initial phase φ (rad) setting t=0 position. Phase (ωt + φ) determines instantaneous state, phase difference Δφ governs interference of two SHM motions. Acceleration: a = -ω² x . ω = 3 s⁻¹, x(0) = 7 sin (π/6) = 7 × 0.5 = 3.5 m . a = -3² × 3.5 = -9 × 3.5 = -31.5 m/s² . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and
Ref: NCERT > Physics Book > Oscillations > Equations of SHM, Phase and Angular Frequency