#rate calculation

Free Fall and Vertical Motion

A car decelerates uniformly from 18m/s to rest over a distance of 36m. What is the deceleration?

Use v2=v02+2ax. Here, v=0, v0=18m/s, x=36m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 36 m/s² as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Free Fall and Vertical Motion

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Integrated Rate Equations - Zero Order Reactions

A reaction has the rate law Rate = k[A][B]². If the concentration of A is tripled and B is halved, what happens to the r

New rate = (3/4) × initial rate.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Integrated Rate Equations - Zero Order Reactions

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Collision Theory - Effective Collisions and Catalyst Effect

For the reaction 2A + B → 3C, the rate of disappearance of B is 0.03 mol L⁻¹ min⁻¹. What is the rate of formation of C?

−Δ[B]/Δt = (1/3) Δ[C]/Δt → Δ[C]/Δt = 3×0.03 = 0.09 mol L⁻¹ min⁻¹.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Collision Theory - Effective Collisions and Catalyst Effect

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Collision Theory - Effective Collisions and Catalyst Effect

For the reaction A + B → 2C, the rate of formation of C is 0.06 mol L⁻¹ min⁻¹. What is the rate of disappearance of A?

Rate = −Δ[A]/Δt = (1/2) Δ[C]/Δt. Given Δ[C]/Δt = 0.06 → −Δ[A]/Δt = 0.03 mol L⁻¹ min⁻¹.

Ref: NCERT Class 12 Chemistry > Chapter 3: Chemical Kinetics > Topic: Collision Theory - Effective Collisions and Catalyst Effect

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