How many significant figures are present in the result of (0.0567 × 273.15)/0.0821?
0.0567 (3 sig figs), 273.15 (5 sig figs), 0.0821 (3 sig figs). Result ≈ 188.56; limited to 3 sig figs (189).
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Reactions in Solutions and Mass Percentage and Numericals