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#mercury

8 public questions tagged with this topic.

Temperature Scales and Triple Point

A 0.15kg mercury block at 400∘C is placed in 0.5kg water at 20∘C in a 0.05kg aluminium calorimeter at 20∘C. Find the fin

0.15×140×(400−T) = (0.5×4186+0.05×900)×(T−20). 8400−21T = (2093+45)×(T−20) = 2138T−42760. 8400+42760 = 2138T+21T. 51160 = 2159T⇒T≈23.7∘C. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 23.7°C. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

Ref: NCERT Class 11 Physics, Chapter 11: Thermal Properties – Calorimetry.

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Fluid Pressure, Pascal's Law and Manometers

A manometer with mercury (ρ\=13.6×103kg/m3) shows a height difference of 20cm. What is the pressure difference? (Take g\

ΔP = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 0.2m. ΔP = 13.6×103×9.8×0.2 = 26656Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.67 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Viscosity, Stokes' Law and Reynolds Number

What is the gauge pressure at a depth of 2.7m in mercury (ρ\=13.6×103kg/m3)? (Take g\=9.8m/s2)

Gauge pressure: Pg = ρgh. ρ = 13.6×103kg/m3, g = 9.8m/s2, h = 2.7m. Pg = 13.6×103×9.8×2.7 = 359856Pa = 3.59856×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.6 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Surface Tension, Capillarity and Excess Pressure

A manometer with mercury (ρ\=13.6×103kg/m3) shows a height difference of 0.28m. What is the pressure difference? (Take g

ΔP = ρgh. ρ = 13.6×103kg/m3, g = 10m/s2, h = 0.28m. ΔP = 13.6×103×10×0.28 = 38080Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.8 × 10⁴ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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