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#magnet division

3 public questions tagged with this topic.

Diamagnetism, Paramagnetism and Ferromagnetism

A bar magnet with original \( m = 2.0 \, \text{A m}^2 \) is cut transversely into two equal parts. What is \( m \) of ea

**Paramagnetism** has small positive χ ≈ 10⁻³ to 10⁻⁵, weakly attracted towards stronger field, random moments align partially with B, magnetization decreases with temperature following Curie law χ ∝ 1/T. Materials have unpaired electrons with permanent moments. When cut transversely, each part has half the original magnetic moment. Given: m = 2.0 A m² . Each part: m' = (2.0/2) = 1.0 A m² . Substituting values gives 1.0 A m², which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.

Ref: NCERT > Physics Book > Magnetism and Matter > Diamagnetism, Paramagnetism and Ferromagnetism

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Magnetic Field Due to Bar Magnet - Axial and Equatorial

A bar magnet with original \( m = 1.6 \, \text{A m}^2 \) is cut transversely into two equal parts. What is \( m \) of ea

**Field due to bar magnet** on axial line is B_axial = (μ₀/4π)·2m/r³, equatorial B_eq = (μ₀/4π)·m/r³, where μ₀/4π = 10⁻⁷ T·m/A, m magnetic moment (A·m²), r distance (m). Axial field twice equatorial at same distance and parallel to moment, equatorial opposite to moment direction. When cut transversely, each part has half the original magnetic moment. Given: m = 1.6 A m² . Each part: m' = (1.6/2) = 0.8 A m² . Substituting values gives 0.8 A m², which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.

Ref: NCERT > Physics Book > Magnetism and Matter > Magnetic Field Due to Bar Magnet - Axial and Equatorial

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Magnetic Field Lines, Bar Magnet and Dipole Moment

A bar magnet is cut transversely into two equal parts. If the original magnetic moment was \( 0.6 \, \text{A m}^2 \), wh

**Magnetic dipole moment** quantifies strength and orientation of magnet, m = 2l × q_m where q_m pole strength. Field line concept visualizes B, with closed nature reflecting absence of magnetic monopoles, explaining non-intersection and continuity. When a bar magnet is cut transversely, each half becomes a magnet with half the original magnetic moment. Given: m = 0.6 A m² . Each part: m' = (0.6/2) = 0.3 A m² . Substituting values gives 0.3 A m², which matches expected magnitude for this magnetic configuration, confirming dipole field dependence on m/r³ and torque relation τ = m B sinθ.

Ref: NCERT > Physics Book > Magnetism and Matter > Magnetic Field Lines, Bar Magnet and Dipole Moment

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