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#Kjeldahl method

3 public questions tagged with this topic.

In the Carius method, 0.15 g of a compound gave 0.287 g of AgCl. If the same sample in Kjeldahl’s method neutralized 10

Mass of Cl = (35.5/143.5) × 0.287 = 0.071 g. Percentage = (0.071/0.15) × 100 = 47.33% ≈ 47%. Kjeldahl’s data is for nitrogen, irrelevant here.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Qualitative and Quantitative Analysis - Lassaigne Test and Estimation

In Kjeldahl’s method, 0.36 g of a compound produced ammonia that neutralized 25 mL of 0.1 M H₂SO₄. What is the percentag

Moles of H₂SO₄ = 0.025 × 0.1 = 0.0025. Moles of NH₃ = 0.005 (2H per H₂SO₄). Mass of N = 0.005 × 14 = 0.07 g. Percentage = (0.07/0.36) × 100 ≈ 19.44%, which rounds to 19%.

Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance