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#gas reaction

5 public questions tagged with this topic.

CHEMISTRY

A gaseous reaction follows Rate = k p_A² with k = 0.1 atm^{-1 s^{-1 and p_A = 0.6 atm . What is the rate in atm s^{-1 ?

Given: A gaseous reaction follows Rate = k p_A² with k = 0.1 atm^{-1 s^{-1 and p_A = 0.6 atm . What is the rate in atm s^{-1 ? These values define the system as per NCERT data. Formula: Rate = k p_A² = 0.1 × (0.6)² = 0.1 × 0.36 = 0.036 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier

For 2A(g) + B(g) 3C(g) , Kp = 2 at 700 K. If PA = 1 atm , PB = 0.5 atm initially, what is PC at equilibrium?

Let PC = 3x , PA = 1 - 2x , PB = 0.5 - x . Kp = ((PC)³/(PA)² PB) = ((3x)³/(1 - 2x)² (0.5 - x)) = 2 , 27x³ = 2 (1 - 2x)² (0.5 - x) , x ≈ 0.2 , PC = 0.6 atm .

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier

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Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases

For 2A(g) + B(g) 2C(g) , Kp = 4 at 500 K. If initial pressures are PA = 2 atm , PB = 1 atm , what is PC at equilibrium?

Let PC = 2x , PA = 2 - 2x , PB = 1 - x . Kp = ((PC)²/PA² PB) = ((2x)²/(2 - 2x)² (1 - x)) = 4 , (4x²/(4 - 4x + 4x²)(1 - x)) = 4 , x ≈ 0.8 , PC = 1.6 atm .

Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Ionic Equilibrium - Acids Bases and pH and Ionization of Weak Acids Bases

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