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#circuit fundamentals

2 public questions tagged with this topic.

What ensures that the total current entering a junction equals the total current leaving it in a complex circuit?

**Kirchhoff's loop rule** (energy conservation) states algebraic sum of potential differences around closed loop zero, Σ ε - Σ I R =0, ensures total voltage drop across series resistors equals source emf. Junction rule (charge conservation) Σ I_in = Σ I_out ensures current continuity. Kirchhoff’s junction rule, based on charge conservation, ensures that charge does not accumulate at a junction in steady state, so the sum of currents in equals the sum out. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation yields Charge

Ref: NCERT > Physics Book > Current Electricity > Kirchhoff's Laws and Combination of Resistors

In a circuit with resistors in series, why does the current remain the same through each resistor?

**Total voltage drop** across series equals source voltage because loop rule Σ V = ε, with internal resistance r included V = ε - I r. For 4 Ω,8 Ω,16 Ω parallel, 1/R_p =1/4+1/8+1/16=7/16, R_p=16/7≈2.29 Ω, then total resistance with internal 3 Ω is 5.29 Ω, current I=18/5.29≈3.4 A. In series, there’s only one path for current. Kirchhoff’s junction rule ensures charge conservation, so the same current flows through each resistor as no charge accumulates. Applying I = n e A v_d, R = ρ l/A, R_t = R₀[1+αΔT], Kirchhoff's ΣI=0, ΣV=0, R_eq series/parallel, V = ε - I r and P = I²R, evaluation

Ref: NCERT > Physics Book > Current Electricity > Kirchhoff's Laws and Combination of Resistors