9 public questions tagged with this topic.
Reduction of 1-nitropropane (CH₃CH₂CH₂NO₂) with H₂/Ni yields propan-1-amine (CH₃CH₂CH₂NH₂), as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions of Amines - Mixed Concept Practice
Reduction of 1-nitrobutane (CH₃CH₂CH₂CH₂NO₂) with H₂/Ni yields butan-1-amine (CH₃CH₂CH₂CH₂NH₂), as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions of Amines - Mixed Concept Practice
Reduction of nitroethane (CH₃CH₂NO₂) with H₂/Ni yields ethylamine (CH₃CH₂NH₂), as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions of Amines - Mixed Concept Practice
Ammonolysis of CH₃CH₂Cl with excess NH₃ favors the formation of the primary amine CH₃CH₂NH₂ (ethylamine), as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Methylamine (CH₃NH₂) is formed directly from CH₃Cl and NH₃ in one step via ammonolysis, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Benzyl chloride (C₆H₅CH₂Cl) with excess NH₃ forms benzylamine (C₆H₅CH₂NH₂) via ammonolysis, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Ammonolysis of CH₃CH₂CH₂Cl with excess NH₃ yields CH₃CH₂CH₂NH₂, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Reaction with Nitrous Acid and Diazonium Salts - Part 2
Ethylamine (CH₃CH₂NH₂) can be prepared by reducing nitroethane (CH₃CH₂NO₂) with H₂/Ni, as per the PDF’s preparation methods.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions - Carbylamine Reaction and General Reactions
