A ball is thrown at 20m/s at 45∘ from a height of 5m. What is its range? (Take g\=10m/s2)
Time of flight: y=v0yt−12gt2, where y=−5m,v0y=20sin45∘=102. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 50 m as the result, so option B is correct.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Acceleration and Velocity Analysis - Part 8