Skip to content

Question

What is the escape speed from a planet with mass 3.6×1024kg and radius 5×106m? (G\=6.67×10−11N m2/kg2)

Options

Choose one · Correct answer highlighted

Explanation

ve = 2GMR. ve = 2×6.67×10−11×3.6×10245×106. ve = 9.607×107≈9.80×103m/s≈9.8km/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9.8 km/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.