Practice question

Given: Three particles of masses 2 kg, 4 kg, and 6 kg are at (0, 2), (3, 0), and (1, 4) respectively. What is the x-coordinate of their nter of mass? Formula: Formula: X = m_1 x_1 + m_2 x_2 + m_3 x_3/m_1 + m_2 + m_3. Substitution & Calculation: Masses: 2, 4, 6 kg ; x-coordinates: 0, 3, 1 . X = (2 × 0) + (4 × 3) + (6 × 1)/2 + 4 + 6 = 0 + 12 + 6/12 = 18/12 = 1.5 m . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.