Practice question
Question
The limiting molar conductivity of BaCl₂ is 280 S cm² mol⁻¹. If λ°Ba²⁺ = 127 S cm² mol⁻¹ , what is λ°Cl⁻ ?
Explanation
Lambdam° = λ°Ba²⁺ + 2λ°Cl⁻ . 280 = 127 + 2λ°Cl⁻ , 2λ°Cl⁻ = 153 , λ°Cl⁻ = 76.5 S cm² mol⁻¹ .
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