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Question

A thin ring of mass 5kg and radius 0.5m has an angular momentum of 12.5kg m2/s. What is its angular velocity?

Options

Choose one · Correct answer highlighted

Explanation

I = MR2 = 5×(0.5)2 = 1.25kg m2. ω = LI = 12.51.25 = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

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