Practice question
Question
A projectile is launched with a speed of 40 m/s at an angle of 30°. What is its velocity at the highest point? (Take g = 10 m/s²)
Explanation
Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 20 m/s. Hence option A satisfies projectile formulas.