Practice question
Question
What is the mass of PbSO₄ produced when 33.1 g of Pb(NO₃)₂ reacts with excess H₂SO₄? (Molar masses: Pb(NO₃)₂ = 331 g/mol, PbSO₄ = 303 g/mol)
Explanation
Reaction: Pb(NO₃)₂ + H₂SO₄ → PbSO₄ + 2HNO₃. Moles of Pb(NO₃)₂ = 33.1/331 = 0.1 mol. 1 mol Pb(NO₃)₂ produces 1 mol PbSO₄; mass = 0.1 × 303 = 30.3 g.
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