Practice question

Given: What is the kinetic energy of a 150 kg satellite at 3 R_E from Earth’s nter? ( M_E = 6 × 10²⁴kg, R_E = 6.4 × 10⁶m, G = 6.67 × 10⁻¹¹N m²/kg² ) These values define the system as per NCERT data. Formula: K = G M_E m/2 r. This is standard NCERT relation. Substitution & Calculation: r = 3 R_E = 1.92 × 10⁷m . K = frac6.67 × 10⁻¹¹ × 6 × 10²⁴ × 1502 × 1.92 × 10⁷. K = frac6.003 × 10¹⁶³.84 × 10⁷approx 1.56 × 10⁹J . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.