Practice question

Given: What is the excess pressure inside a water drop of radius 2.5 mm at 100° C ? (Surface tension = 0.3 × 10⁻³N/m ) Formula: Excess pressure: Δ P = 2 S/r. Substitution & Calculation: S = 0.3 × 10⁻³N/m, r = 2.5 × 10⁻³m . Δ P = frac2 × 0.3 × 10⁻³².5 × 10⁻³= 0.24 Pa . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.