Practice question

Given: What is the critical angle for a diamond ( n = 2.42 ) to water ( n = 1.33 ) interface? Formula: Critical angle: sin i_c = n_2/n_1. Substitution & Calculation: Diamond ( n_1 = 2.42 ), water ( n_2 = 1.33 ). sin i_c = 1.33/2.42 approx 0.55 . i_c = sin^{-1(0.55) approx 33.4° . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.