Practice question
Question
What is the critical angle for a dense flint glass ( n = 1.62 ) to air interface?
Explanation
Given:
What is the critical angle for a dense flint glass ( n = 1.62 ) to air interface?
These values define the system as per NCERT data.
Formula:
Critical angle: sin i_c = n_2/n_1.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Glass ( n_1 = 1.62 ), air ( n_2 = 1 ). sin i_c = 1/1.62 approx 0.617 . i_c = sin^{-1(0.617) approx 38.1° .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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