Practice question

Given: What is the angular position of the first minimum in a single-slit diffraction pattern if the slit width is 5.0 μm and the wavelength is 500 nm ? These values define the system as per NCERT data. Formula: First minimum occurs at sin θ = lambda/a. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: lambda = 5.0 × 10⁻⁷ m, a = 5.0 × 10⁻⁶ m . sin θ = frac5.0 × 10⁻⁷⁵.0 × 10⁻⁶= 0.1, θ = sin^{-1(0.1) approx 5.7° . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.