Practice question

Given: The solubility of PbCl₂ in water is 1.0 × 10⁻²M. What is its K_{sp ? These values define the system as per NCERT data. Formula: PbCl₂(s) <=> Pb²+ + 2Cl-, [Pb²+] = S, [Cl-] = 2S. This is standard NCERT relation. Substitution & Calculation: K_{sp = [Pb²+][Cl-]² = S · (2S)² = 4S³ = 4 (1.0 × 10⁻²)³ = 4 × 10⁻⁶. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.