Practice question

Given: What volume of 1.5 M HCl is required to react completely with 10 g of CaCO₃? (Molar mass of CaCO₃ = 100 g/mol) These values define the system as per NCERT data. Formula: Moles of CaCO₃ = 10 / 100 = 0.1 mol. This is standard NCERT relation. Substitution & Calculation: Reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O. . Moles of HCl = 0.1 × 2 = 0.2 mol. Volume = 0.2 / 1.5 = 0.1333 L = 133.3 mL ≈ 133 mL. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.