Practice question
Question
The magnetic potential energy of a dipole with \( m = 0.6 \, \text{A m}^2 \) in a field \( B = 0.3 \,
\text{T} \) at \( 60^\circ \) is:
Explanation
**Torque on magnetic dipole** in uniform field B is τ = m × B, magnitude τ = m B sinθ, m moment (A·m²), B field (T), θ angle between m and B (degrees). Torque tends to align moment with field, zero at θ = 0°, maximum mB at 90°, direction given by right-hand rule. U_m = -m B cosθ . Given: m = 0.6 A m² , B = 0.3 T , θ = 60° , cos 60° = 0.5 . Substitute: U_m = -0.6 × 0.3 × 0.5 = -0.09 J . Substituting values gives -0.09 J, which matches expected magnitude for this magnetic
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.