Practice question
Question
In projectile motion, what remains constant throughout the trajectory, assuming no air resistance?
Explanation
Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields Horizontal velocity. Hence option B satisfies projectile formulas.
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