Practice question

Given: In a single-slit diffraction experiment, if the slit width is 2.5 μm and the wavelength is 500 nm, what is the angle of the first minimum? These values define the system as per NCERT data. Formula: First minimum occurs at sin θ = lambda/a. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: lambda = 500 nm = 5.0 × 10⁻⁷ m, a = 2.5 μm = 2.5 × 10⁻⁶ m . sin θ = frac5.0 × 10⁻⁷².5 × 10⁻⁶= 0.2, so θ = sin^{-1(0.2) approx 11.5° . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.