Practice question

Given: Calculate the de Broglie wavelength of an electron moving at 2.05 × __10POW₇__m s^{-1 . ( h = 6.626 × 10⁻³⁴J s, m_e = 9.1 × 10⁻³¹kg ) These values define the system as per NCERT data. Formula: lambda = h/mv = frac6.626 × 10⁻³⁴⁹.1 × 10⁻³¹ × 2.05 × __10POW₇__= 3.55 × 10⁻¹¹m .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.