Practice question
Question
A wire of length 0.8 m carrying 5 A is at 30° to a magnetic field of 0.8 T . What is the force on the wire?
Explanation
Given:
A wire of length 0.8 m carrying 5 A is at 30° to a magnetic field of 0.8 T . What is the force on the wire?
Formula:
Force F = I l B sin θ.
Substitution & Calculation:
F = 5 × 0.8 × 0.8 × sin 30° = 4 × 0.8 × 0.5 = 1.6 N .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Discussion
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