Practice question
Question
A wheel with moment of inertia 5kg m2 rotates at 3rad/s. A torque of 10Nm acts for 5s. What is its final angular velocity?
Explanation
α = τI = 105 = 2rad/s2. Δω = αt = 2×5 = 10rad/s. ω = ω0+Δω = 3+10 = 13rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 13 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
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