Practice question
Question
A reaction’s rate constant is 1.0 × 10⁻² s⁻¹ at 27°C. If the activation energy is 50 kJ/mol, what is the rate constant at 37°C (R = 8.314 J mol⁻¹ K⁻¹)?
Explanation
log(k₂/k₁) ≈ 0.281 → k₂ ≈ 1.91 × 10⁻² s⁻¹.
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